\documentclass[12pt]{jsarticle}
\usepackage{amsmath,amssymb}
\pagestyle{empty}
\begin{document}
\setlength{\baselineskip}{22pt}
\begin{flushleft}
{\huge 4}
　関係式$\displaystyle\int_0^xf(t)dt=e^x-ae^{2x}\int_0^1f(t)e^{-t}dt$を満たす
連続関数$f(x)$と定数$a$を求めよ．
\end{flushleft}
\end{document}
